RE: Lithium palladium vs. "normal" palladium
I forgot to say I use 40% AFO. I checked the figures (something I had to do earlier): Remember the formula in the book "The New Platinum Print"? 1.7g LiCl + 2.3g PdCl2 + water to make 25ml 2.3g PdCl2 in 25ml will give 2.3 / 177.33 (1) x 1000 (2) / 25 (3) = 0.51M Li2[PdCl4] solution Notes: (1) Molar mass of PdCl2 (2) Molar concentration = matter in 1000ml (3) Formula is for 25ml, therefore I had to interpolate by multiplying the amnt. with 1000 / 25 to find the molar concentration (see 2). According to 2:1 ratio of AFO to Li2[PdCl4], I have to use 0.51 x 2 = 1.02M AFO (in other words: 1.02 x 428.067 (1) ~= 436g in 1000ml (43.6%). It seems that my iron solution is substantially weak - will try 45% later... I'm not confused about point #1 (in my previous message) anymore. Notes: (1) Molar mass of AFO Regards, Loris. Quoting Loris Medici <mail@loris.medici.name>: ... (I always had the feeling that I was loosing Pd when doing Ziatypes, because the clearing bath was a light shade Pd brown - instead of the yellow I get in other iron processes...) This is confusion #1... ...
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