[alt-photo] Re: chemical conversion
John Brewer
john at johnbrewerphotography.com
Wed Feb 8 12:59:17 GMT 2012
Thanks Loris and Cor
So my method was correct but my g/mol weight was wrong. I got the
CdBr2.4H2O weight from here
http://www.wolframalpha.com/entities/chemicals/cadmium_bromide_tetrahydrate/22/em/qe/
Thanks
John
On 7 February 2012 11:59, <C.Breukel at lumc.nl> wrote:
> Loris..you beat me, well is saves me typing..;-)..
>
> Best,
>
> Cor
>
> > -----Original Message-----
> > From: alt-photo-process-list-bounces at lists.altphotolist.org [mailto:alt-
> > photo-process-list-bounces at lists.altphotolist.org] On Behalf Of Loris
> > Medici
> > Sent: dinsdag 7 februari 2012 12:58
> > To: The alternative photographic processes mailing list
> > Subject: [alt-photo] Re: chemical conversion
> >
> > John,
> >
> > CdBr2.4H2O -> 344.280g/mole (NOT 290.23g/mole!!!)
> > CdBr2 -> 272.219g/mole
> >
> > 344.280 / 272.219g = 1.2647
> >
> > Therefore, since tetrahydrate is *heavier* than anhydrous, you have to
> > use 1.26g (26% more) tetrahydrate where the formula calls 1g
> > anhydrous.
> >
> > Hope this helps,
> > Loris.
> >
> > P.S. Molar mass figures from this site:
> > http://environmentalchemistry.com/yogi/reference/molar.html
> >
> >
> > 2012/2/7 John Brewer <john at johnbrewerphotography.com>:
> > > Hello list members
> > >
> > > I want to convert quantity by weight of CdBr2 4H2O to CdBr2. Am I right
> > in
> > > thinking that the maths is 290.23g/mol over 272.22g/mol = 1.07 and I
> > > multiply the CdBr2 4H2O by 1.07 to get the equivalent of CdBr2?
> > >
> > > Thanks
> > >
> > > John
> > >
> > > --
> > > www.johnbrewerphotography.com
> > > 2012 Wetplate Collodion Workshop
> > > Dates<
> http://www.johnbrewerphotography.com/wetplate-collodion-workshops>
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--
www.johnbrewerphotography.com
2012 Wetplate Collodion Workshop
Dates<http://www.johnbrewerphotography.com/wetplate-collodion-workshops>
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