[alt-photo] Re: chemical conversion

[Eric Neilsen]

Yes, that is two of us. 

Eric Neilsen
4101 Commerce Street, Suite 9
Dallas, TX 75226
214-827-8301

www.ericneilsenphotography.com
SKYPE ejprinter

-----Original Message-----
From: alt-photo-process-list-bounces at lists.altphotolist.org
[mailto:alt-photo-process-list-bounces at lists.altphotolist.org] On Behalf Of
C.Breukel at lumc.nl
Sent: Tuesday, February 07, 2012 5:59 AM
To: alt-photo-process-list at lists.altphotolist.org
Subject: [alt-photo] Re: chemical conversion

Loris..you beat me, well is saves me typing..;-)..

Best,

Cor

> -----Original Message-----
> From: alt-photo-process-list-bounces at lists.altphotolist.org 
> [mailto:alt- photo-process-list-bounces at lists.altphotolist.org] On 
> Behalf Of Loris Medici
> Sent: dinsdag 7 februari 2012 12:58
> To: The alternative photographic processes mailing list
> Subject: [alt-photo] Re: chemical conversion
> 
> John,
> 
> CdBr2.4H2O -> 344.280g/mole (NOT 290.23g/mole!!!)
> CdBr2 -> 272.219g/mole
> 
> 344.280 / 272.219g = 1.2647
> 
> Therefore, since tetrahydrate is *heavier* than anhydrous, you have to 
> use 1.26g (26% more) tetrahydrate where the formula calls 1g 
> anhydrous.
> 
> Hope this helps,
> Loris.
> 
> P.S. Molar mass figures from this site:
> http://environmentalchemistry.com/yogi/reference/molar.html
> 
> 
> 2012/2/7 John Brewer <john at johnbrewerphotography.com>:
> > Hello list members
> >
> > I want to convert quantity by weight of CdBr2 4H2O to CdBr2. Am I 
> > right
> in
> > thinking that the maths is 290.23g/mol over 272.22g/mol = 1.07 and I 
> > multiply the CdBr2 4H2O by 1.07 to get the equivalent of CdBr2?
> >
> > Thanks
> >
> > John
> >
> > --
> > www.johnbrewerphotography.com
> > 2012 Wetplate Collodion Workshop
> > Dates<http://www.johnbrewerphotography.com/wetplate-collodion-worksh
> > ops> _______________________________________________
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