[alt-photo] Re: chemical conversion

[John Brewer]

>You can see why you made the mistake.

No, I'm not sure. I AM sure that I remember having molar headaches at high
school though...

J

On 8 February 2012 18:02, Eric Neilsen <ejnphoto at sbcglobal.net> wrote:

> You can see why you made the mistake. Formula and compound formula have a
> different write up on their site.
>
> Eric Neilsen
> 4101 Commerce Street, Suite 9
> Dallas, TX 75226
> 214-827-8301
>
> www.ericneilsenphotography.com
> SKYPE ejprinter
>
>
> -----Original Message-----
> From: alt-photo-process-list-bounces at lists.altphotolist.org
> [mailto:alt-photo-process-list-bounces at lists.altphotolist.org] On Behalf
> Of
> John Brewer
> Sent: Wednesday, February 08, 2012 6:59 AM
> To: The alternative photographic processes mailing list
> Subject: [alt-photo] Re: chemical conversion
>
> Thanks Loris and Cor
>
> So my method was correct but my g/mol weight was wrong. I got the
> CdBr2.4H2O
> weight from here
>
> http://www.wolframalpha.com/entities/chemicals/cadmium_bromide_tetrahydrate/
> 22/em/qe/
>
> Thanks
>
> John
>
> On 7 February 2012 11:59, <C.Breukel at lumc.nl> wrote:
>
> > Loris..you beat me, well is saves me typing..;-)..
> >
> > Best,
> >
> > Cor
> >
> > > -----Original Message-----
> > > From: alt-photo-process-list-bounces at lists.altphotolist.org
> > > [mailto:alt- photo-process-list-bounces at lists.altphotolist.org] On
> > > Behalf Of Loris Medici
> > > Sent: dinsdag 7 februari 2012 12:58
> > > To: The alternative photographic processes mailing list
> > > Subject: [alt-photo] Re: chemical conversion
> > >
> > > John,
> > >
> > > CdBr2.4H2O -> 344.280g/mole (NOT 290.23g/mole!!!)
> > > CdBr2 -> 272.219g/mole
> > >
> > > 344.280 / 272.219g = 1.2647
> > >
> > > Therefore, since tetrahydrate is *heavier* than anhydrous, you have
> > > to use 1.26g (26% more) tetrahydrate where the formula calls 1g
> > > anhydrous.
> > >
> > > Hope this helps,
> > > Loris.
> > >
> > > P.S. Molar mass figures from this site:
> > > http://environmentalchemistry.com/yogi/reference/molar.html
> > >
> > >
> > > 2012/2/7 John Brewer <john at johnbrewerphotography.com>:
> > > > Hello list members
> > > >
> > > > I want to convert quantity by weight of CdBr2 4H2O to CdBr2. Am I
> > > > right
> > > in
> > > > thinking that the maths is 290.23g/mol over 272.22g/mol = 1.07 and
> > > > I multiply the CdBr2 4H2O by 1.07 to get the equivalent of CdBr2?
> > > >
> > > > Thanks
> > > >
> > > > John
> > > >
> > > > --
> > > > www.johnbrewerphotography.com
> > > > 2012 Wetplate Collodion Workshop
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>
>
>
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> 2012 Wetplate Collodion Workshop
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