Jeffrey D. Mathias (jeffrey.d.mathias@worldnet.att.net)
Sun, 09 May 1999 16:54:59 -0400
SORRY
Please note that I have discovered an error in my modified formula for
the solution of Lithium Palladium Chloride. I somehow got the wrong
weight for the sensitizer by misplacing the "3" in the exposure
reaction. This also effects the number of metal salts to balance the
equation which is now one for one. Plus I added the three H2O to the
sensitizer. This will alter things as follows (although not much as I
had both multiplied and divided by three):
For the Ziatype variation, Ferric Ammonium Oxalate is used as the
sensitizer with a basic reaction as follows:
3[(NH4)Fe2(C2O4)3+3H2O] =(via exposure)= 6Fe(C2O4) + 3(C2O4) + 3NH4
(or this is attached to something) + 9H2O
The basic Pt/Pd process reaction with Lithium substituted is:
6Fe(C2O4) + 3Li2PdCl4 = 2Fe2(C2O4)3 + 2(FeCl3) + 6LiCl + 3Pd
To balance this, each (NH4)3Fe2(C2O4)3 will require <ONE> Li2PdCl4
<<<<<<<<<<<<<
Looking up the molecular weights of the ingredients:
FW of (NH4)Fe2(C2O4)3+3(H2O) is 447.83 <<<<<<<<<<<<<<
FW of Li2PdCl4 is 262.09
FW of LiCl is 42.39
FW of PdCl2 is 177.31
If the (NH4)3Fe2(C2O4)3 is mixed at 40.00 g/100ml,
it follows that the Li2PdCl4 should be mixed at 23.41 g/100ml.
<<<<<<<<<<<<
(262.09/447.83)*40.00 = 23.41 <<<<<<<<<<<<<<<<<<<
Now, Li2PdCl4 = 2LiCl + PdCl2
which if the Li2PdCl4 is a solution of 23.41 %, then
LiCl is a solution of 7.57 % and
PdCl2 is a solution of 15.84 %
(2*(42.39)/262.09)*23.41 = 7.57
(177.31/262.09)*23.41 = 15.84
This means that the formula should be:
7.57 g LiCl
15.84 g PdCl2
100 ml H2O
My modified formula posted earlier seems to have too little palladium as
well. I plan to make more prints with this higher palladium
concentration. It is expected that as more palladium salt is added
print quality will increase. Indeed the prints thus far have
demonstrated this. However more prints need to be made to determine the
optimized concentration of Pd salt. I will keep increasing the amount
of Pd until there is no detectible change in print quality or the
solution is saturated., and then report the results.
IS THERE A CHEMIST IN THE HOUSE?
Have I gone about this in the right way?
Although it does make sense that as long as the print quality is
increasing to keep increasing the amount of metal salt.
-- Jeffrey D. Mathias http://home.att.net/~jeffrey.d.mathias/
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