Erich,
Thank you it is very intéressant
Are you possible to describe the
process with a little texte with the quantité of chemical
2
FeCl3 + 6 NH4OH --> 2 Fe(OH)3 + 6 NH4Cl
2 Fe(OH)3 + 3 H2C2O4 ---> Fe2(C2O4)3 + 6 H2O
162 g. FeCl3 --> 107 g. Fe(OH)3
107 g. Fe(OH)3 needs 87 g. H2C2O4
25 g.
FeCl3 = 40 g. FeCl3.6 H2O
Thank you it is very interesting but I did not
understand everything Know you write the successive stages with
chemicals and quantities of chemicals
Thank you for your help
Philippe