RE: Dilution question
BTW another way of doing it (longer but easy to remember) would be:
Let's assume you need to mix 100ml 0.125% solution.
100ml x (1)0.125% = 0.125g / (2)10% = 1.25ml 10% + (3)98.75ml water = 100ml
1 is to find how much solid compound you beed per given target volume
2 is to find how much original stock solution you need for fulfilling 1
3 is topping with water to target volume
From: Jon Reid [mailto:email@example.com] On Behalf Of Jonathan Reid
Sent: Thursday, September 10, 2009 2:28 PM
Subject: Re: Dilution question
On 10/09/2009, at 7:42 PM, Loris Medici wrote:
> 10% (source dilution) / 0.125% (target dilution) = 80 times stronger,
> therefore you'll use 1 part 10% + 79 parts water (1 + 79 = 80) to make
> a 0.125% solution from 10%...
> From: firstname.lastname@example.org [mailto:email@example.com] On Behalf
> Of Jon Reid
> Sent: Thursday, September 10, 2009 11:47 AM
> To: alt-photo-process-l
> Subject: Dilution question
> Hi list,
> Can anyone help me figure out the following dilution? I have a
> solution that is 10% potassium chlorate. I have in the past diluted
> this down to 5% and 1% and a 1/2% solutions. I rarely use any and
> cannot find my notes for making the dilutions.
> I now want to make a tiny dilution, like 0.125%, or similar, just so
> there is a presence of potassium chlorate in the sensitiser. Could
> someone help me get there from the 10% start?