RE: Dilution question
You're welcome. BTW another way of doing it (longer but easy to remember) would be: Let's assume you need to mix 100ml 0.125% solution. 100ml x (1)0.125% = 0.125g / (2)10% = 1.25ml 10% + (3)98.75ml water = 100ml 0.125% 1 is to find how much solid compound you beed per given target volume 2 is to find how much original stock solution you need for fulfilling 1 3 is topping with water to target volume -----Original Message----- From: Jon Reid [mailto:sharperstill@gmail.com] On Behalf Of Jonathan Reid Sent: Thursday, September 10, 2009 2:28 PM To: alt-photo-process-l@usask.ca Subject: Re: Dilution question thank you! On 10/09/2009, at 7:42 PM, Loris Medici wrote: > 10% (source dilution) / 0.125% (target dilution) = 80 times stronger, > therefore you'll use 1 part 10% + 79 parts water (1 + 79 = 80) to make > a 0.125% solution from 10%... > > ________________________________ > > From: sharperstill@gmail.com [mailto:sharperstill@gmail.com] On Behalf > Of Jon Reid > Sent: Thursday, September 10, 2009 11:47 AM > To: alt-photo-process-l > Subject: Dilution question > > > Hi list, > > Can anyone help me figure out the following dilution? I have a > solution that is 10% potassium chlorate. I have in the past diluted > this down to 5% and 1% and a 1/2% solutions. I rarely use any and > cannot find my notes for making the dilutions. > > I now want to make a tiny dilution, like 0.125%, or similar, just so > there is a presence of potassium chlorate in the sensitiser. Could > someone help me get there from the 10% start? > > regards, > > Jon > > -- > http:www.sharperstill.com
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