[alt-photo] Re: chemical conversion

[Loris Medici]

John,

CdBr2.4H2O -> 344.280g/mole (NOT 290.23g/mole!!!)
CdBr2 -> 272.219g/mole

344.280 / 272.219g = 1.2647

Therefore, since tetrahydrate is *heavier* than anhydrous, you have to
use 1.26g (26% more) tetrahydrate where the formula calls 1g
anhydrous.

Hope this helps,
Loris.

P.S. Molar mass figures from this site:
http://environmentalchemistry.com/yogi/reference/molar.html


2012/2/7 John Brewer <john at johnbrewerphotography.com>:
> Hello list members
>
> I want to convert quantity by weight of CdBr2 4H2O to CdBr2. Am I right in
> thinking that the maths is 290.23g/mol over 272.22g/mol = 1.07 and I
> multiply the CdBr2 4H2O by 1.07 to get the equivalent of CdBr2?
>
> Thanks
>
> John
>
> --
> www.johnbrewerphotography.com
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