Formaldehyde is a gas at standard condition and the liquid form you see
is an aquaous solution of the gas. This is probably what you are trying
to relate to.
On Mon, 26 Dec 2005 09:08:07 -0800, "Jack Fulton"
<jefulton1@comcast.net> said:
> Of course, I am not sure Chris, but I believe you might actually be
> using 'formalin', which is 37% formaldehyde. I believe that
> formaldehyde iin its pure form is difficult to obtain . . but I may
> be incorrect.
> Jack Fulton
Received on Mon Dec 26 11:48:46 2005
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