comparsi wrote:
> Yes, exactly. In this case, 5.09g.
> Best regards
> Comparsi
>
>> I just need a quick refresher...when a formula calls for
>> moles I need to convert it to grams. Do I just multiply
>> moles by molecular weight to get grams required?. ie where
>> 03 moles are required and the molecular weight is 169.87
>> (silver nitrate) the product is the grams required?
Just wanted to be sure. Thank you both.
~m
Received on Tue Oct 4 10:41:05 2005
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