Re: chemistry help

Philippe Monnoyer (Philippe.Monnoyer@fundp.ac.be)
Wed, 20 Aug 1997 11:53:24 +0200

Dear Nicole,

In two words, the percentage of your solutions is a (weight of
salt)/(weight of solution) percentage, which in the case of water as a
solvant may be considered as a (weight of salt)/(weight of the solution
considered to be water). It means that :
For a 10% solution of Sodium Chloride for example, if you want to make 1
liter solution (which will weight approx. 1kg, if with water) take 10% of
the weight in salt , it means 100g and add enough water to make a volume of
1 liter. This is the most accepted approximation with % concentrations.
And that's it.

Yours,

Philippe MONNOYER
That's all

At 14:22 20/08/97 +1000, you wrote:
>
>could someone please help me with a little chemistry question as I have
>very limited chemical knowledge. I want to make different percentage
>solutions of Ferric Ammonium Citrate and Potassium ferricyanide (for
>example a 10%, a 15%, a 20% right through to a 45% solution of both
>chemicals) and have been told that it is not merely done by adding 10
>parts powder 90 parts water or so on due to molecular weights. I was
>wondering if anyone could tell me how I go about determining what is right
>for both substances. If you could include exactly how you calculated it
>it would be a great help
>
>Thanks
>Nici Churchill
>
>
>