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Marek...thanks.
Yes, the recipe I have calls for mono which would add 18
to the anhydrous weight, if I'm not mistaken. So multiplying the mono amount by
.885 gives me the weight in anhydrous form...again, if I'm not
mistaken.
The form you've referenced has 1.5 molecules of water
(sesqui-hydrate?) which adds 27 to the anhydrous weight, giving 165.2, as
listed.
I will make sure the developer is on the acidic
side...thanks.
Paul
----- Original Message -----
Sent: Wednesday, May 20, 2009 9:07
AM
Subject: RE: converting anhydrous to
mono...?
Paul,
Potassium carbonate is listed as K2CO3x1.5H2O
FW165.23, for the anhydrous FW is 138.21
I do not see monohydrate. CHeck on
this one more time. For the formula listed above you would need
138.21/165.23=0.8365 multiplied by the weight called for by the
recipe.
make sure that your developer is on the acidic side. I keep some
crystals of undissolved acid on the bottom. Watch the foaming as you add the
carbonate.
Marek
> Date: Wed, 20 May 2009 08:11:56
-0700
> From: viapiano@pacbell.net
> Subject: converting anhydrous
to mono...?
> To: alt-photo-process-l@usask.ca
>
> Hi
all...
>
> I'm making PO developer today and I need to convert
anyhdrous Potassium
> Carbonate (what I have) to its mono (what I need)
equivalent in weight.
>
> Does anyone have the conversion factor
and a reference...?
>
> Much thanks...
>
> Paul
>
>
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